Problem 5-7
The following activities are part of a project to be scheduled using CPM:
ACTIVITY | IMMEDIATE PREDECESSOR | TIME (WEEKS) |
A | — | 7 |
B | A | 6 |
C | A | 2 |
D | C | 4 |
E | B D | 3 |
F | D | 4 |
G | E F | 6 |
b. What is the critical path?
A-C-D-F-G | |
A-C-D-E-G | |
A-B-E-G | |
A-B-D-F-G |
c. How many weeks will it take to complete the project?
Number of weeks
d. How much slack does activity B have?
Slack of activity B week(s)
step 1 | find early start, and early finish from the start of the project for each activity |
step 2 | Find Maximum EF and keep it as the LF of last activities. Max of EF's is 23 |
Activity | Duration, D | Early start, ES=Max of early finish of preceding activities | Early finish, EF = ES + D | Late finish, LF= Min of LS of successor activities | Late start, LS= LF - D | Total slack= LF-EF | Critical activity, activities with 0 slack time |
A | 7 | 0 | 7 | ||||
B | 6 | 7 | 13 | ||||
C | 2 | 7 | 9 | ||||
D | 4 | 9 | 13 | ||||
E | 3 | 13 | 16 | ||||
F | 4 | 13 | 17 | ||||
G | 6 | 17 | 23 | 23 |
step 3 | calculate LS for each activity after calculating its EF |
Activity | Duration, D | Early start, ES=Max of early finish of preceding activities | Early finish, EF = ES + D | Late finish, LF= Min of LS of successor activities | Late start, LS= LF - D | Total slack= LF-EF | Critical activity, activities with 0 slack time |
A | 7 | 0 | 7 | 7 | 0 | 0 | Yes |
B | 6 | 7 | 13 | 14 | 8 | 1 | No |
C | 2 | 7 | 9 | 9 | 7 | 0 | Yes |
D | 4 | 9 | 13 | 13 | 9 | 0 | Yes |
E | 3 | 13 | 16 | 17 | 14 | 1 | No |
F | 4 | 13 | 17 | 17 | 13 | 0 | Yes |
G | 6 | 17 | 23 | 23 | 17 | 0 | Yes |
b: A-C-D-F-G is the critical path.
c: it will take 23 weeks
d: B has 1 week of slack
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