A manufacturer claims that the mean lifetime of its fluorescent bulbs is 1500 hours. A homeowner selects 40 bulbs and finds the mean lifetime to be 1490 hours with a population standard deviation of 80 hours. Test the manufacturers claim. Use a=0.05. Show graph as well.
Solution:
Here, we have to use one sample z test for the population mean.
The null and alternative hypotheses are given as below:
Null hypothesis: H0: the mean lifetime of its fluorescent bulbs is 1500 hours.
Alternative hypothesis: Ha: the mean lifetime of its fluorescent bulbs is not 1500 hours.
H0: µ = 1500 versus Ha: µ ≠ 1500
This is a two tailed test.
The test statistic formula is given as below:
Z = (Xbar - µ)/[σ/sqrt(n)]
From given data, we have
µ = 1500
Xbar = 1490
σ = 80
n = 40
α = 0.05
Critical value = -1.96 and 1.96
(by using z-table or excel)
Z = (1490 – 1500)/[80/sqrt(40)]
Z = -0.7906
P-value = 0.4292
(by using Z-table)
P-value > α = 0.05
So, we do not reject the null hypothesis
There is sufficient evidence to conclude that the mean lifetime of its fluorescent bulbs is 1500 hours.
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