If n=160 and ˆpp^ (p-hat) =0.28, find the margin of error at a
90% confidence level
Give your answer to three decimals
Solution :
Given that,
n = 160
Point estimate = sample proportion = = 0.28
1 - = 1 - 0.28 = 0.72
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z 0.05 = 1.645
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.645 * (((0.28 * 0.72) /160 )
E = 0.058
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