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If n=280 and ˆpp^ (p-hat) =0.71, find the margin of error at a 99% confidence level...

If n=280 and ˆpp^ (p-hat) =0.71, find the margin of error at a 99% confidence level

Give your answer to three decimals

Math   Statistics-And-Probability   
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Answer #1

Solution :

Given that,

n = 280

= 0.71

1 - = 1 - 0.71 = 0.29

At 99% confidence level the z is ,

= 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

Z/2 = Z0.005 = 2.576

Margin of error = E = Z / 2 * [( * (1 - )] / n)

= 2.576 * ([(0.71 * 0.29)] / 280)

= 0.070

Margin of error at a 99% confidence level is 0.070

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