a) If n=390 and ˆpp^ (p-hat) =0.88, find the margin of error at
a 99% confidence level
Give your answer to three decimals
b)Out of 200 people sampled, 44 had kids. Based on this,
construct a 99% confidence interval for the true population
proportion of people with kids.
Give your answers as decimals, to three places
c) If n=25, ¯xx¯(x-bar)=32, and s=2, construct a confidence
interval at a 90% confidence level. Assume the data came from a
normally distributed population.
Give your answers to one decimal place.
a. z value for 99% CI is 2.576 as P(-2.576<z<2.576)=0.99
So Margin of Error is
b. z value for 99% CI is 2.576 as P(-2.576<z<2.576)=0.99
So Margin of Error is
So CI is
c. t table value for 90% is TINV(0.1,24)=1.711
So Margin of Error is
So CI is
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