Question

If n=460 and ˆpp^ (p-hat) =0.52, find the margin of error at a 95% confidence level

Give your answer to three decimals

Answer 1

Solution :

Given that,

n = 460

Point estimate = sample proportion = =0.52

1 - = 1 - 0.52=0.48

At 95% confidence level

= 1 - 95%

=1 - 0.95 =0.05

/2 = 0.025

Z/2 = Z _{0.025 = 1.96}

Margin of error = E = Z _{/ 2} * (( * (1 - )) / n)

= 1.96 (((0.52*0.48) /460 )

e = 0.046