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the wave function of Ψ(θ/ϕ) =sin (θ) cos (ϕ) the eigen-function of Lz ? of L^2...

the wave function of Ψ(θ/ϕ) =sin (θ) cos (ϕ) the eigen-function of Lz ? of L^2 ?

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Answer #1

Hence is not an eigenfunction of the operator LZ .

Now

Hence the wave function is an eigenfunction for the operator L2

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