A spring has a constant of 270 N/m. A mass of 83 kg is attached to the spring, pulled down a distance of 5 meters and then released.
Solution:
Given,
spring constant k=270N/m
mass m=83 Kg
The mass is streched to a distance of 5m. Therefore, amplitude a =5m.
The angular velocity is given by,
(a)The displacement of a body in SHM is given by,.
i.e,
so, at t= 2 s
(b) The velocity of the body is given by,
Get Answers For Free
Most questions answered within 1 hours.