Question

solve the differential equation...

(x^{2}-1)(dy/dx)+xy=0

Answer #1

Solve the Differential Equation:
(2y^4 + xy)dx - (6x^2) dy= 0

Solve the differential equation
a2 (dy - dx) = x2 dy + y2
dx
a is a constant

solve the bernqoulli equation dy/dx+xy+xy^2=0

Solve the Homogeneous differential equation
(7 y^2 + 1 xy)dx - 1 x^2 dy = 0
(a) A one-parameter family of solution of the equation is y(x)
=
(b) The particular solution of the equation subject to the
initial condition y(1) =1/7.

solve diffeential equation.
( x2y +xy -y )dx + (x2 y -2 x2)
dy =0 answer x + ln x + x-1 + y- 2 lny = c
dy / dx + 2y = e-2x - x^2 y (0) =3 answer
y = 3 e -2s + e-2x ( intefral of e
-s^2ds ) s is power ^ 2 means s to power of
2

Solve the special type second order differential
equation:
x2*d2y/dx^2+x(dy/dx)=1

solve differential equation ((x)2 - xy +(y)2)dx - xydy
= 0
solve differential equation (x^2-xy+y^2)dx - xydy =
0

Consider the differential equation
x2 dy + y ( x + y) dx = 0 with the initial condition
y(1) = 1.
(2a) Determine the type of the differential equation. Explain
why?
(2b) Find the particular solution of the initial value problem.

Solve the given differential equations:
a) dy/dx=(x+1)^2
b) (x+1)dy/dx-xy=x^2+x

(x-y)dx + (y+x)dy =0 Solve the differential equation

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