Question

solve differential equation ((x)2 - xy +(y)2)dx - xydy = 0

solve differential equation (x^2-xy+y^2)dx - xydy = 0

Answer #1

Solve the Homogeneous differential equation
(7 y^2 + 1 xy)dx - 1 x^2 dy = 0
(a) A one-parameter family of solution of the equation is y(x)
=
(b) The particular solution of the equation subject to the
initial condition y(1) =1/7.

Solve the differential equation
y^' − xy = e^x y(0) = 2

(x-y)dx + (y+x)dy =0 Solve the differential equation

Consider the following differential equation: dy/dx =
−(3xy+y^2)/x^2+xy
(a) Rewrite this equation into the form M(x, y)dx + N(x, y)dy =
0. Determine if this equation is exact;
(b) Multiply x on both sides of the equation, is the new
equation exact?
(c) Solve the equation based on Part (a) and Part (b).

Use the method for solving homogeneous equations to solve the
following differential equation.
(9x^2-y^2)dx+(xy-x^3y^-1)dy=0
solution is F(x,y)=C, Where C= ?

Solve the Differential Equation:
(2y^4 + xy)dx - (6x^2) dy= 0

solve the differential equation...
(x2-1)(dy/dx)+xy=0

solve differential equation
(x^2)y'' - xy' +y =2x

Solve the differential equation
(1-y)dx-x^2y^2dy=0

Solve the following differential equation using taylor series
centered at x=0:
(2+x^2)y''-xy'+4y = 0

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