Question

Solve the given differential equations:

a) dy/dx=(x+1)^2

b) (x+1)dy/dx-xy=x^2+x

Answer #1

Homogeneous Differential Equations:
dy/dx = xy/x^(2) - y^(2)
dy/dx = x^2 + y^2 / 2xy

Solve the following differential equations.
a.) dy/dx+2xy=x, y(0)=2
b.) ?^2(dy/dx)−?y=−y^2

Use the method for solving homogeneous equations to solve the
following differential equation.
(9x^2-y^2)dx+(xy-x^3y^-1)dy=0
solution is F(x,y)=C, Where C= ?

Use the Laplace transform to solve the given system of
differential equations. 2 dx/dt + dy/dt − 2x = 1
dx/dt + dy/dt − 6x − 6y = 2
x(0) = 0, y(0) = 0

Solve the given system of differential equations by systematic
elimination. 2 dx/dt − 6x + dy/dt = e^t
dx/dt − x + dy/dt = 6e^t

differential equations solve
(2xy+6x)dx+(x^2+4y^3)dy, y(0)=1

Solve the Homogeneous differential equation
(7 y^2 + 1 xy)dx - 1 x^2 dy = 0
(a) A one-parameter family of solution of the equation is y(x)
=
(b) The particular solution of the equation subject to the
initial condition y(1) =1/7.

solve the differential equation...
(x2-1)(dy/dx)+xy=0

Solve the given differential equation
y-x(dy/dx)=3-2x2(dy/dx)

Given each of the equations below, find dy/dx:
(a)x^2y=x^2+y^2
(b) (x+1)/x= 1−xy
(c) siny=x^2−1

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