Question

solve diffeential equation.

( x^{2}y +xy -y )dx + (x^{2} y -2 x^{2})
dy =0 answer x + ln x + x^{-1} + y- 2 lny = c

dy / dx + 2y = e^{-2x - x}^{^2} y (0) =3 answer
y = 3 e ^{-2s} + e^{-2x} ( intefral of e
^{-s^2}ds ) s is power ^ 2 means s to power of
2

Answer #1

Solve the equation.
(2x^3+xy)dx+(x^3y^3-x^2)dy=0
give answer in form F(x,y)=c

solve the differential equation...
(x2-1)(dy/dx)+xy=0

Solve the Differential Equation:
(2y^4 + xy)dx - (6x^2) dy= 0

solve the give diffential equation.
x dy/dx + xy= 1-y y(1)=0 answer y = x-1( 1-
e1-x )

solve the bernqoulli equation dy/dx+xy+xy^2=0

Solve the Homogeneous differential equation
(7 y^2 + 1 xy)dx - 1 x^2 dy = 0
(a) A one-parameter family of solution of the equation is y(x)
=
(b) The particular solution of the equation subject to the
initial condition y(1) =1/7.

1) Solve the given differential equation by separation of
variables.
exy
dy/dx = e−y +
e−6x −
y
2) Solve the given differential
equation by separation of variables.
y ln(x) dx/dy = (y+1/x)^2
3) Find an explicit solution of the given initial-value
problem.
dx/dt = 7(x2 + 1), x( π/4)= 1

Determine the type of below equations and solve it.
a-)(sin(xy)+xycos(xy)+2x)dx+(x2cos(xy)+2y)dy=0
b-)(t-a)(t-b)y’-(y-c)=0 a,b,c are
constant.

solve differential equation ((x)2 - xy +(y)2)dx - xydy
= 0
solve differential equation (x^2-xy+y^2)dx - xydy =
0

Evaluate ∮C(x^3+xy)dx+(cos(y)+x2)dy∮C(x^3+xy)dx+(cos(y)+x^2)dy
where C is the positively oriented boundary of the region bounded
by C:0≤x^2+y^2≤16, x≥0,y≥0C:0≤x^2+y^2≤16,x≥0,y≥0

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