In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a nonbrowser, light browser, or heavy browser. For each shopper, the study obtained a measure to determine how comfortable the shopper was in a store. Higher scores indicated greater comfort. Suppose the following data were collected.
Light | Heavy | |||
Nonbrowser | Browser | Browser | ||
7 | 6 | 5 | ||
8 | 7 | 7 | ||
9 | 6 | 5 | ||
6 | 5 | 7 | ||
6 | 8 | 4 | ||
7 | 5 | 6 | ||
8 | 7 | 5 | ||
7 | 6 |
7 |
a. Calculate the value of the test statistic (to 2 decimals, if necessary).
b. Use Fisher's LSD procedure to compare the comfort levels of nonbrowsers and light browsers. Use .
Compute the LSD critical value (to 2 decimals).
Applying one way ANOVA: (use excel: data: data analysis: one way ANOVA: select Array): |
Source | SS | df | MS | F | P value |
Between | 9.33 | 2 | 4.67 | 4.00 | 0.0337 |
Within | 24.50 | 21 | 1.17 | ||
Total | 33.83 | 23 |
a)
test statistic = | 4.00 |
b)
critical value of t with 0.05 level and N-k=21 degree of freedom= | tN-k= | 2.080 | |||
Fisher's (LSD) for group i and j =(tN-k)*(sp*√(1/ni+1/nj) = | 1.12 |
Difference | Absolute Value | Conclusion |
x1-x2 | 1.00 | not significant difference |
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