Question

In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a nonbrowser, light browser, or heavy browser. For each shopper, the study obtained a measure to determine how comfortable the shopper was in a store. Higher scores indicated greater comfort. Suppose the following data were collected.

Non Browser	Light Browser	Heavy Browser
8	9	10
9	10	12
10	9	10
7	8	12
7	11	9
8	8	11
9	10	10
8	9	12

A. use .05 to test for a difference among mean comfort scores for the three types of browsers .

Compute the values identified below (to two decimals)

Sum of Squares, Treatment
Sum of Squares, Error
Mean Squares, Treatment
Mean Squares, Error

Calculate the value of the test statistic

T = ?

B. Use Fisher's LSD procedure to compare the comfort levels of nonbrowsers and light browsers. use .05

Compute the LSD Critical Value

Answer 1

A)

From the ANOVA results in R studio,

Ap value is less than 0.05(level of significance).

Therefore we reject null hypothesis at 5% level of significance.

i.e. Tjeth significant difference in the mean comfort score of three types of browser.

Sum of squares and mean sum of squares are mentioned at anova table.in r output

B)

By LSD test in r,

For comparison of non browser and light browser p value is 0.07819 which is greater than 0.05(level of significance).

Therefore there is no significant differences in mean comfort score of non browser and light browser.