Question

In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a nonbrowser, light browser, or heavy browser. For each shopper, the study obtained a measure to determine how comfortable the shopper was in a store. Higher scores indicated greater comfort. Suppose the following data were collected.

		Light	Heavy
	Nonbrowser	Browser	Browser
	6	7	3
	7	8	5
	8	7	3
	5	6	5
	5	9	2
	6	6	4
	7	8	3
	6	7	5

a. Use a=.05 to test for a difference among mean comfort scores for the three types of browsers.

Compute the values identified below (to 2 decimals, if necessary).

Sum of Squares, Treatment
Sum of Squares, Error
Mean Squares, Treatment
Mean Squares, Error

Calculate the value of the test statistic (to 2 decimals, if necessary).

The P-value is - Select your answer -

less than .01

between .01 and .025

between .025 and .05

between .05 and .10

greater than .10

What is your conclusion?

- Select your answer -

Conclude that the mean comfort scores are not all the same for the browser groups

Do not reject the assumption that the mean comfort scores are equal for the browser groups

b. Use Fisher's LSD procedure to compare the comfort levels of nonbrowsers and light browsers. Use a=.05 .

Compute the LSD critical value (to 2 decimals).

What is your conclusion?

- Select your answer -

Conclude that nonbrowsers and light browsers have different mean comfort scores

Cannot conclude that nonbrowsers and light browsers have different mean comfort scores

Answer 1

a.

Sum of Squares, Treatment	52.00
Sum of Squares, Error	24.50
Mean Squares, Treatment	26.000
Mean Squares, Error	1.17

Calculate the value of the test statistic (to 2 decimals, if necessary).

22.29

The P-value is less than .01.

What is your conclusion?

Conclude that the mean comfort scores are not all the same for the browser groups

b.

Compute the LSD critical value (to 2 decimals).

1.12

What is your conclusion?

Cannot conclude that nonbrowsers and light browsers have different mean comfort scores