tennis player hits a ball at ground level, giving it an initial velocity of 25.0m/s at 56.0? above the horizontal. |
Part A What are the horizontal vh and vertical vv components of the ball's initial velocity? Enter your answers separated by a comma.
SubmitMy AnswersGive Up Correct Term 1: Significant Figures Feedback: Your
answer 13.98 m/s, m/s was either rounded differently or
used a different number of significant figures than required for
this part. Part B How high above the ground does the ball go?
SubmitMy AnswersGive Up Correct Significant Figures Feedback: Your answer 21.86 m was either rounded differently or used a different number of significant figures than required for this part. Part C How long does it take the ball to reach its maximum height?
SubmitMy AnswersGive Up Correct Part D What is the ball's velocity at its highest point?
SubmitMy AnswersGive Up Correct Part E What is the ball's acceleration at its highest point?
SubmitMy AnswersGive Up Correct Part F For how long a time is the ball in the air?
SubmitMy AnswersGive Up Correct Significant Figures Feedback: Your answer 4.22 s was either rounded differently or used a different number of significant figures than required for this part. Part G When this ball lands on the court, how far is it from the place where it was hit?
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I'll start from where you left ! The only acceleration of ball is equal to 9.8m/s2 in vertically downward direction due to gravity. The ball does not experience any force in the horizontal direction and therby, no horizontal acceleration.
This means that horizontal component of velocity remains the same throughout the flight and is equal to initial horizontal velocity vh= 25cos56o=13.98m/s. The total time of flight (as calculated by you) is T=4.23 sec.
The horizontal distance travelled by it is thus d = vh * T =13.98*4.23= 59.13 metres.
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