Question

The delivery times for all food orders at a fast-food restaurant during the lunch hour are...

The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 10.7 minutes and a standard deviation of 4.6 minutes. Let x¯ be the mean delivery time for a random sample of 10 orders at this restaurant. Calculate the mean and standard deviation of x¯.

Round your answers to two decimal places.

Mean of x¯=____  minutes

Standard deviation of x¯=____  minutes

Homework Answers

Answer #1

Solution :

Given that ,

mean = = 10.70

standard deviation = = 4.6

n = 10

Mean of x¯ = = 10.70

Standard deviation of x¯= =  / n= 4.6 / 10=1.45

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The waiting time until a customer is served at a fast food restaurant during lunch hours...
The waiting time until a customer is served at a fast food restaurant during lunch hours has a skewed distribution with a mean of 2.4 minutes and a standard deviation of 0.4 minute. Suppose that a random sample of 44 waiting times will be taken. Compute the probability that the mean waiting time for the sample will be longer than 2.5 minutes. Answer: (Round to 4 decimal places.)
During lunch hour, customers arrive at a fast-food restaurant at the rate of 120 customers per...
During lunch hour, customers arrive at a fast-food restaurant at the rate of 120 customers per hour. The restaurant has one line, with three workers taking food orders at independent service stations. Each worker takes an exponentially distributed amount of time–on average 1 minute–to service a customer. Let Xt denote the number of customers in the restaurant (in line and being serviced) at time t. The process (Xt)t≥0 is a continuous-time Markov chain. Exhibit the generator matrix.
1. A restaurant serves an average of 180 customers per hour during the lunch time. (a)....
1. A restaurant serves an average of 180 customers per hour during the lunch time. (a). What probability distribution is most appropriate for calculating the probability of a given number of customers arriving within one hour during lunch time? (b). What are the mean and the standard deviation of the number of customers this restaurant serves in one hour during lunch time? (c). Would it be considered unusually low if only 150 customers showed up to this restaurant in one...
You are the manager of a restaurant for a​ fast-food franchise. Last​ month, the mean waiting...
You are the manager of a restaurant for a​ fast-food franchise. Last​ month, the mean waiting time at the​ drive-through window for branches in your geographical​ region, as measured from the time a customer places an order until the time the customer receives the​ order, was 3.7 minutes. You select a random sample of 64 orders. The sample mean waiting time is 3.41 ​minutes, with a sample standard deviation of 0.8 minute. Find the​ p-value. p-value= ( ) ​(Round to...
A sample of 50 days showed that a fast food restaurant served an average of 182...
A sample of 50 days showed that a fast food restaurant served an average of 182 customers during lunch time. The standard deviation of he sample was 8. Find the 90% confidence interval for the mean.
The frequency in which a restaurant receives​ on-line delivery orders follows an exponential distribution with a...
The frequency in which a restaurant receives​ on-line delivery orders follows an exponential distribution with a mean of 10.36 minutes between orders. Using this​ information, complete parts ​(a) through ​(f) for this question. a) The probability that the restaurant will receive their next​ on-line delivery order in less than 5.1 minutes is ​(Round to four decimal places as​ needed.) ​b) The probability that the restaurant will wait between 9 and 11.4 minutes after getting a new​ on-line delivery order is...
28. You are the manager of a restaurant for a​ fast-food franchise. Last​ month, the mean...
28. You are the manager of a restaurant for a​ fast-food franchise. Last​ month, the mean waiting time at the​ drive-through window for branches in your geographical​ region, as measured from the time a customer places an order until the time the customer receives the​ order, was 3.8 minutes. You select a random sample of 81 orders. The sample mean waiting time is 3.99 minutes, with a sample standard deviation of 0.9 minute. At the 0.10 level of​ significance, is...
1. You are the manager of a fast-food restaurant. The business problem is to determine whether...
1. You are the manager of a fast-food restaurant. The business problem is to determine whether the population mean waiting time to place an order has changed in the past month from its previous population mean value of 4.5 minute. From the past experience, you can assume that the population is normally distributed, with a population standard deviation of 1.2 minutes. You select a sample of 25 orders during a one-hour period. The sample mean is 5.1 minutes. Determine whether...
You are the manager of a restaurant for a​ fast-food franchise. Last​ month, the mean waiting...
You are the manager of a restaurant for a​ fast-food franchise. Last​ month, the mean waiting time at the​ drive-through window for branches in your geographical​ region, as measured from the time a customer places an order until the time the customer receives the​ order, was 3.7 minutes. You select a random sample of 81 orders. The sample mean waiting time is 3.41 ​minutes, with a sample standard deviation of 0.9 minute. At the 0.01 level of​ significance, is there...
The hourly wage for workers in a fast food restaurant is Normally distributed with a mean...
The hourly wage for workers in a fast food restaurant is Normally distributed with a mean of $5.85 and a standard deviation of $0.35. If a worker is selected at random, find the probability that: a. (S)he earns less than $5.50 an hour b. (S)he earns between $5.90 and $6.40 an hour c. (S)he earns at least $6.00 an hour