The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 10.7 minutes and a standard deviation of 4.6 minutes. Let x¯ be the mean delivery time for a random sample of 10 orders at this restaurant. Calculate the mean and standard deviation of x¯.
Round your answers to two decimal places.
Mean of x¯=____ minutes
Standard deviation of x¯=____ minutes
Solution :
Given that ,
mean = = 10.70
standard deviation = = 4.6
n = 10
Mean of x¯ = = 10.70
Standard deviation of x¯= = / n= 4.6 / 10=1.45
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