A sample of 50 days showed that a fast food restaurant served an average of 182 customers during lunch time. The standard deviation of he sample was 8. Find the 90% confidence interval for the mean.
Formula for Confidence Interval for Population mean when population Standard deviation is not known
Sample Average number of customers served during lunch time : = 182
Sample size : n= 50
Sample Standard deviation : s= 8
Given | |
Sample Mean : | 182 |
Sample Standard Deviation : s | 8 |
Sample Size : n | 50 |
Degrees of freedom : n-1 | 49 |
Confidence Level : | 90 |
= (100-90)/100 | 0.1 |
/2 | 0.05 |
1.6766 |
90% confidence interval for the mean.
90% confidence interval for the mean. = =(180.1031,183.8969)
Get Answers For Free
Most questions answered within 1 hours.