Question

# A sample of 50 days showed that a fast food restaurant served an average of 182...

A sample of 50 days showed that a fast food restaurant served an average of 182 customers during lunch time. The standard deviation of he sample was 8. Find the 90% confidence interval for the mean.

Formula for Confidence Interval for Population mean when population Standard deviation is not known

Sample Average number of customers served during lunch time : = 182

Sample size : n= 50

Sample Standard deviation : s= 8

 Given Sample Mean : 182 Sample Standard Deviation : s 8 Sample Size : n 50 Degrees of freedom : n-1 49 Confidence Level : 90 = (100-90)/100 0.1 /2 0.05 1.6766

90% confidence interval for the mean.

90% confidence interval for the mean. = =(180.1031,183.8969)

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