You are the manager of a restaurant for a fast-food franchise. Last month, the mean waiting time at the drive-through window for branches in your geographical region, as measured from the time a customer places an order until the time the customer receives the order, was
3.7 minutes. You select a random sample of 64 orders. The sample mean waiting time is 3.41 minutes, with a sample standard deviation of 0.8 minute.
Find the p-value.
p-value= ( )
(Round to THREE decimal places as needed.)
Solution :
= 3.7
= 3.41
s = 0.8
n = 64
This is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 3.7
Ha : 3.7
Test statistic = t
= ( - ) / s / n
= (3.7- 3.41) / 0.8 / 64
= − 2.90
Test statistic t value = − 2.90
P-value = 0.005
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