Question

The waiting time until a customer is served at a fast food restaurant during lunch hours...

The waiting time until a customer is served at a fast food restaurant during lunch hours has a skewed distribution with a mean of 2.4 minutes and a standard deviation of 0.4 minute. Suppose that a random sample of 44 waiting times will be taken. Compute the probability that the mean waiting time for the sample will be longer than 2.5 minutes. Answer: (Round to 4 decimal places.)

Math   Statistics-And-Probability   
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Answer #1

Solution :

Given that ,

mean = = 2.4

standard deviation = = 0.4

n = 44

= 2.4 and

= / n = 0.4 / 44 = 0.0603

P( > 2.5) = 1 - P( < 2.5)

= 1 - P(( - ) / < (2.5 - 2.4) / 0.0603)

= 1 - P(z < 1.6584)

= 1 - 0.9514

= 0.0486

Probability = 0.0486

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