If n = 320 and ˆpp^ (p-hat) = 0.05, construct a 90% confidence
interval.
Give your answers to three decimals
_< p >_
Solution :
Given that,
Point estimate = sample proportion = = 0.05
Z/2 = 1.3645
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.645 * (((0.05 * 0.95) / 320)
= 0.020
A 90% confidence interval for population proportion p is ,
- E < p < + E
0.05 - 0.020 < p < 0.05 + 0.020
0.030 < p < 0.070
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