If n=300 and p^ (p-hat) = 0.38, construct a 99% confidence
interval.
Give your answers to three decimals.
____< p <____
99% confidence interval for p is
- Z/2 * sqrt [ ( 1 - ) / n ] < p < + Z/2 * sqrt [ ( 1 - ) / n ]
0.38 - 2.576 * sqrt ( 0.38 ( 1- 0.38) / 300) < p < 0.38 + 2.576 * sqrt ( 0.38 ( 1- 0.38) / 300)
0.308 < p < 0.452
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