Question

Calculate the rotational inertia of a meter stick, with mass 0.633 kg, about an axis perpendicular to the stick and located at the 27.4 cm mark. (Treat the stick as a thin rod.)

Answer #1

Calculate the rotational inertia of a meter stick with mass
m=0.56 kg about an axis perpendicular to set stick and located at
the 20 cm mark. (Treat the stick as a thin rod).

A particle of mass 0.350 kg is attached to the 100-cm mark of a
meter stick of mass 0.125 kg. The meter stick rotates on a
frictionless, horizontal table with an angular speed of 6.00
rad/s.
(a) Calculate the angular momentum of the system when the stick
is pivoted about an axis perpendicular to the table through the
50.0-cm mark.
_____ kg · m2/s
(b) Calculate the angular momentum of the system when the stick
is pivoted about an axis...

A
uniform meter stick is suspended at the 10cm mark mark on the
stick. It swings as a physical pendulum. The equation for the
moment of inertia of a thin rod rotated about an axis through the
center is 1/12 ML^2.
a) What is the rotational inertia in terms of M?
b) What is the period of the pendulum?

A particle of mass 0.300 kg is attached to the 100 cm mark of a
meter stick of mass 0.200 kg. The meter stick rotates on a
horizontal, frictionless table with an angular speed of 4.00
rad/s.]
(a) Calculate the angular momentum of the system when the stick
is pivoted about an axis perpendicular to the table through the
75.0 cm mark.
(b) What is the angular momentum when the stick is pivoted about
an axis perpendicular to the table...

A
meter stick that has a mass of 90 grams is suspended from the 20
centimeter mark and set swinging freely.
1.Calculate the rotational inertia.
2. Calculate the period of the resulting small amplitude
oscillation.

Calculate the moment of inertia of a thin rod rotating about an
axis through its center perpendicular to its long dimension. Do the
same for rotation about an axis through one of the ends
(perpendicular to the length again). Does this confirm the parallel
axis theorem? Remember ?? = ? ??C????.

The rotational inertia I of any given body of mass
M about any given axis is equal to the rotational inertia
of an equivalent hoop about that axis, if the hoop has the
same mass M and a radius k given by
The radius k of the equivalent hoop is called the
radius of gyration of the given body. Using this formula,
find the radius of gyration of (a) a cylinder of
radius 3.72 m, (b) a thin spherical shell...

A particle of mass 0.350 kg is attached to the 100-cm mark of a
meterstick of mass 0.150 kg. The meterstick rotates on the surface
of a frictionless, horizontal table with an angular speed of 6.00
rad/s.
(a) Calculate the angular momentum of the system when the stick
is pivoted about an axis perpendicular to the table through the
50.0-cm mark.
(b) Calculate the angular momentum of the system when the stick
is pivoted about an axis perpendicular to the...

A mass of 1.9 kg is located at the end of a very light and rigid
rod 44 cm in length. The rod is rotating about an axis at its
opposite end with a rotational velocity of 5 rad/s.
(a) What is the rotational inertia of the system?
(b) What is the angular momentum of the system?

A thin, rigid, uniform rod has a mass of 1.40 kg and a length of
2.50 m. (a) Find the moment of inertia of the rod relative to an
axis that is perpendicular to the rod at one end. (b) Suppose all
the mass of the rod were located at a single point. Determine the
perpendicular distance of this point from the axis in part (a),
such that this point particle has the same moment of inertia as the
rod...

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