Question

A uniform meter stick is suspended at the 10cm mark mark on the stick. It swings...

A uniform meter stick is suspended at the 10cm mark mark on the stick. It swings as a physical pendulum. The equation for the moment of inertia of a thin rod rotated about an axis through the center is 1/12 ML^2.
a) What is the rotational inertia in terms of M?
b) What is the period of the pendulum?
Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the rotational inertia of a meter stick with mass m=0.56 kg about an axis perpendicular...
Calculate the rotational inertia of a meter stick with mass m=0.56 kg about an axis perpendicular to set stick and located at the 20 cm mark. (Treat the stick as a thin rod).
Calculate the rotational inertia of a meter stick, with mass 0.633 kg, about an axis perpendicular...
Calculate the rotational inertia of a meter stick, with mass 0.633 kg, about an axis perpendicular to the stick and located at the 27.4 cm mark. (Treat the stick as a thin rod.)
A meter stick that has a mass of 90 grams is suspended from the 20 centimeter...
A meter stick that has a mass of 90 grams is suspended from the 20 centimeter mark and set swinging freely. 1.Calculate the rotational inertia. 2. Calculate the period of the resulting small amplitude oscillation.
A thin 1 m long uniform rod with a total mass of 750g is suspended vertically...
A thin 1 m long uniform rod with a total mass of 750g is suspended vertically at the upper end. The moment of inertia of the rod in respect to the center of mass is mL*2/12 (where L is the total lenght of the rod). A 9 g bullet is shot to the lower end of the rod and embeds there. The bullet speed before impact is 580 m/s. Calculate the amount of energy transfered to the heat during the...
A uniform meter stick swings about a pivot point which is a distance x = 35.2...
A uniform meter stick swings about a pivot point which is a distance x = 35.2 cm from the end of the stick. What is its period of oscillation?
A physical pendulum consists of a meter stick that is pivoted at a small hole drilled...
A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance d from the 50 cm mark. The period of oscillation is 6.3 s. Find d. in m.
A thin uniform rod with mass m swings about an axis that passes through one end...
A thin uniform rod with mass m swings about an axis that passes through one end of the rod and is perpendicular to the plane of the swing. The rod swings with a period T and an angular amplitude of φm (assume this angle is sufficiently small to allow for the use of the equations in this chapter). (a) What is the length of the rod? (b) What is the maximum kinetic energy of the rod as it swings? State...
A physical pendulum consists of a meter stick that is pivoted at a small hole drilled...
A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance d from the 50 cm mark. The period of oscillation is 2.54 s. Find d.
A physical pendulum consists of a meter stick that is pivoted at a small hole drilled...
A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance d from the 50 cm mark. The period of oscillation is 6 s. Find d.
A thin, uniform rod is bent into a square of side length a. If the total...
A thin, uniform rod is bent into a square of side length a. If the total mass of the rod is M, find the moment of inertia about an axis through the center and perpendicular to the plane formed by the interior of the square. Thanks!
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT