Question

Directions: Convert the following problem below to c++ equivalent code

Problem 5:

1. Take a random number from the user
2. Multiply the number by 4
3. Add 1 to the number
4. Multiply by the original number that the user input
5. Subtract the original number away
6. Take the square root of the number (you can use cmath’s sqrt function)
7. Divide the number by 2
8. The result should be the original number

Problem 8:

For this problem I want you to draw out a flow chart to illustrate the logic. You may use word, DIA, or any other software you choose but be specific on the symbols used to illustrate this problem. If you use hand drawn, make sure the paper is unlined and that your picture of it is clear and legible. Please submit this problem as an image file

1. Take any random 2 digit number
2. Divide the number by 2
3. Add 17 to the number
4. If the first digit (10’s place) of the number is greater than the last than add the first digit to the number, otherwise add the second digit (1’s place)
5. If the number is greater than 21 subtract the product of the 2 digits.
   1. Repeat this until the number is less than 21
6. Output the results of the number

Answer 1

PROBLEM 5

C++ PROGRAM

#include<iostream>
#include<math.h>
using namespace std;
int main()
{
   int n,x;;
   cout<<endl<<"Enter a number";
   cin>>n;
   x=n;//assign the user entry number to x
   x=x*4; //multiply x by 4
   x=x+1;//add 1 to x
   x=x*n;//multiply x by user entry number
   x=x-n;//subtract the user entry number from x
   x=sqrt(x); //find the square root of x
   x=x/2;//devide x by 2
   if(x==n) //check whether x and n equal or not. The result will always will be trur
   cout<<endl<<"Equal";
   else
   cout<<endl<<"Unequal";
}

OUTPUT

PROBLEM 8

FLOWCHART USING FLOWGARITHM

OUTPUT

FLOWCHART INLARGE SIZE

C++ PROGRAM

#include<iostream>
#include<math.h>
using namespace std;
int main()
{
   int x,a,b;;
   do
   {
           cout<<endl<<"Enter a number";
   cin>>x;//input the number
   }while(x<10 || x>99);//check for 2 digit or not

  
   do
   {
   x=x/2;//devide by 2
   x=x+17;//add 17
   a=x %10;//find the unit place digit
   b=x/10;//find the 10's place digit
   if(b>a) //compare b with a and do the necessary action
   x=x+b;
   else
   x=x+a;
   if(x>21) //check whether the number greater to 21 or not
   x=x-(a*b);   //subtract (a*b)if greater to 21
   }while(x<21);//continue the process till the number less than 21
   cout<<endl<<"nUMBER IS "<<x;//display the number
}

OUTPUT