Question

Directions: Convert the following problems below to c++ equivalent code

Problem 6:

1. Get a random number from the user
2. Remember the original number
3. Add 3 to the number
4. Double the number
5. and then multiply by
6. Knock off the last digit (remove the 1’s place)
7. Finally remove the original number
8. What is the result?

Problem 7:

1: Have the person write down any three digits number with decreasing digits (432 or 875).
2: Reverse the number you wrote in #1.
3: Subtract the number obtained in #2 from the number you wrote in #1 (#1 - #2)
4: Reverse the number obtained in #3
5: Add the numbers found in #3 and #4

What is the answer?

Answer 1

6.

CODE

#include <iostream>

using namespace std;

int main() {

int num;

cout << "Enter a number: ";

cin >> num;

int i = num;

num += 3;

num *= 2;

num /= 10;

num -= i;

cout << num;

}

7.

CODE

#include <iostream>

using namespace std;

int main() {

int num;

cout << "Enter a 3-digit number: ";

cin >> num;

int i = num, reverse = 0, rem;

while(num != 0)

{

rem = num % 10;

reverse = reverse * 10 + rem;

num /= 10;

}

int diff = i - reverse;

i = diff;

reverse = 0;

while(diff != 0)

{

rem = diff % 10;

reverse = reverse * 10 + diff;

diff /= 10;

}

cout << (i + reverse);

}