Question

A sag vertical curve has the PVC at station 88+00 and PVT at station 94+25. The back grade is -3.5% and the forward grade is +2%. The length of the vertical curve is.................ft

Answer #1

A 1,800 ft. long sag vertical curve (equal tangent) has PVC at
Station 145+10 and elevation 1,280 ft. The initial grade is -2.5%
and final grade is +4.8%. Determine the elevation and stationing of
PVI and PVT.

Please I need The right answer for this question as soon as
possible.
A sag vertical curve (equal tangent) has PVI at station 212+00
and elevation 540.75 ft. The initial grade is -2.5% and the final
grade is +4.5%. The length of the curve is 900 ft. Determine the
following,
1. Stationing of the low point, PVC, and PVT.
2. Elevation at station 213+00, PVC, low point, and PVT.

Determine the elevations for each standard station between PVC
and PVT from a vertical curve connecting a 3% slope to a -5% slope.
The PVC and PVT stations are 112 + 22 and 119 + 64, respectively.
The elevation of the PVI is 1235 feet.

An equal tangent sag vertical curve is 600 ft long (i.e. 6
stations). The elevation of PVC is 1000 ft. The initial grade is
-0.035 ft/ft (-3.5%) and the final grade is +0.005 ft/ft (+0.5%).
What is the elevation of a point that is 350 ft (3.5 stations) from
PVC?
A) 1005.42 ft
B)991.83 ft
C) 991.01 ft
D) 996.83 ft

An existing equal-tangent sag vertical curve is designed for 60
mi/h. The initial grade is -3% and the elevation of the PVT is 754
ft. The PVC of the curve is at station 134 + 16 and the PVI is at
137 + 32. An overpass is being constructed directly above the PVI.
The highway is for cars only (AASHTO minimum and recommended
structure clearances do not apply) and the overpass design assumes
the driver's eye height is set conservatively...

An
existing equal-tangent sag vertical curve is designed for 60 mi/h.
The initial grade is -3% and the elevation of the PVT is 754 ft.
The PVC of the curve is at station 134 + 16 and the PVI is at 137 +
32. An overpass is being constructed directly above the PVI. The
highway is for cars only (AASHTO minimum and recommended structure
clearances do not apply) and the overpass design assumes the
driver's eye height is set conservatively...

A vertical parabolic sag curve of Lapulapu underpass has grade
of -4% followed by a grade of +2% intersecting at station 12+150.80
at elevation 124.80 m. above sea level. The change of grade of the
sag curve is restricted to 6%.
Compute the length of curve.
Compute the elevation of the lowest point of the curve.
Compute the elevation at station 12+125.60

The PVI of a vertical curve is at station 110 + 00 and elevation
1100.00 ft. The vertical curve is equal tangent, 600ft long, and
connects an initial grade of +1.30% and a final grade of –1.10%.
The vertical curve crosses a 3ft diameter pipe at right angles. The
pipe is located at station 112 + 00 and its centerline is at
elevation 1093.00 ft.
a) Using offsets, determine the depth, below the surface of the
curve, to the top...

An equal-tangent crest vertical curve is being designed for a
speed of 55 mph. The curve connects grades of 2% and -3.5% in the
direction of interest. The curve high point is at station 110+00
and has an elevation of 500 ft. What is the station and elevation
of the PVC and the PVI?

Problem #4: Vertical curve
A vertical curve is define by gradient lines. The gradient of
the back tangent is +4.2% and the
gradient of the forward tangent is -3.75%. The BVC station is at
45+00 and has an elevation of
215.00 feet. For a vertical curve with a length of 12 stations,
determine the following:
a. The station and elevation of the PVI.
b. The station and elevation of the EVC.
c. The elevation of the vertical curve at station...

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