Question

A vertical parabolic sag curve of Lapulapu underpass has grade of -4% followed by a grade...

A vertical parabolic sag curve of Lapulapu underpass has grade of -4% followed by a grade of +2% intersecting at station 12+150.80 at elevation 124.80 m. above sea level. The change of grade of the sag curve is restricted to 6%.

  1. Compute the length of curve.
  2. Compute the elevation of the lowest point of the curve.
  3. Compute the elevation at station 12+125.60

Homework Answers

Answer #1

vertical parabolic sag

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A parabolic curve has a descending grade of -0.8% which meets an ascending grade of 0.6%...
A parabolic curve has a descending grade of -0.8% which meets an ascending grade of 0.6% at station 10+020. The maximum allowable change of grade per 20 m station is 0.20%. Elevation at station 10+020 is 240.60 m. a) Compute the length of the curve; b) Compute the horizontal distance of the lowest point from station 10+020; c) Compute for the vertical distance from PI to the curve; d) Compute the elevation of the lowest point of the curve; e)...
A vertical summit parabolic curve has vertical offset of 0.375 m. from the curve to the...
A vertical summit parabolic curve has vertical offset of 0.375 m. from the curve to the grade tangent at Station 10 + 050. The curve has a slope of +4% and -2% grades intersecting at the P.I. The offset distance of the curve at P.I. is equal to 1.5m. If the stationing of the P.C. is at 10 + 000. Compute the (a) required length of curve (b) horizontal distance of the vertical curve turning point from the point of...
A vertical parabolic curve is to connect a back tangent of -3% and a forward tangent...
A vertical parabolic curve is to connect a back tangent of -3% and a forward tangent of +4%. The change of grade is 0.60% per 20 m station. The stationing of PC is 17+428 with an elevation of 200 m. Compute the: a) length of the parabolic curve; b) stationing of PT (format: 00+000.00); c) elevation of PT; d) elevation of the lowest point of the curve; e) elevation at Station 17+544.67.
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade...
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade of +1.5%. The PVI of the two grades is at station 33 + 75 and elevation of 540 m above the datum level. The elevation at station 34 + 40 must be 541 m above the datum level in order to Accommodate a street, which crosses the road. Determine; ( According to TRH17) i. The length of the curve. ii. The elevation and station...
A sag vertical curve has the PVC at station 88+00 and PVT at station 94+25. The...
A sag vertical curve has the PVC at station 88+00 and PVT at station 94+25. The back grade is -3.5% and the forward grade is +2%. The length of the vertical curve is.................ft
Please I need The right answer for this question as soon as possible. A sag vertical...
Please I need The right answer for this question as soon as possible. A sag vertical curve (equal tangent) has PVI at station 212+00 and elevation 540.75 ft. The initial grade is -2.5% and the final grade is +4.5%. The length of the curve is 900 ft. Determine the following, 1. Stationing of the low point, PVC, and PVT. 2. Elevation at station 213+00, PVC, low point, and PVT.
A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The...
A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The length of the curve is 450.00 ft. The intersection of the grades is at 10+00 and the elevation at that point is 440.00. Compute the elevation of the +00 points on the curve. Then determine the location and elevation of the highest point on the curve. If there is an existing bridge at this location over the proposed road, and the elevation of its...
the rate of change of the grade of a parabolic summit curve is 0.5%. the grade...
the rate of change of the grade of a parabolic summit curve is 0.5%. the grade of ascending and descending tangents are 6% and -2.0% respectively. the elecation of VPT is 200 ft at Sta 15+80. determine the: a.) length of curve b.) elecation of the summit c.)location of the summit d.)the vertical distance from VPI to the curve e.)elevation at Sta 06+80
A 1,800 ft. long sag vertical curve (equal tangent) has PVC at Station 145+10 and elevation...
A 1,800 ft. long sag vertical curve (equal tangent) has PVC at Station 145+10 and elevation 1,280 ft. The initial grade is -2.5% and final grade is +4.8%. Determine the elevation and stationing of PVI and PVT.
An existing equal-tangent sag vertical curve is designed for 60 mi/h. The initial grade is -3%...
An existing equal-tangent sag vertical curve is designed for 60 mi/h. The initial grade is -3% and the elevation of the PVT is 754 ft. The PVC of the curve is at station 134 + 16 and the PVI is at 137 + 32. An overpass is being constructed directly above the PVI. The highway is for cars only (AASHTO minimum and recommended structure clearances do not apply) and the overpass design assumes the driver's eye height is set conservatively...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT