Question

An equal tangent sag vertical curve is 600 ft long (i.e. 6 stations). The elevation of...

An equal tangent sag vertical curve is 600 ft long (i.e. 6 stations). The elevation of PVC is 1000 ft. The initial grade is -0.035 ft/ft (-3.5%) and the final grade is +0.005 ft/ft (+0.5%). What is the elevation of a point that is 350 ft (3.5 stations) from PVC?

A) 1005.42 ft

B)991.83 ft

C) 991.01 ft

D) 996.83 ft

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 1,800 ft. long sag vertical curve (equal tangent) has PVC at Station 145+10 and elevation...
A 1,800 ft. long sag vertical curve (equal tangent) has PVC at Station 145+10 and elevation 1,280 ft. The initial grade is -2.5% and final grade is +4.8%. Determine the elevation and stationing of PVI and PVT.
A 182.880m equal tangent sag curve has the PVC at station 5+181.600 and elevation 304.800m. The...
A 182.880m equal tangent sag curve has the PVC at station 5+181.600 and elevation 304.800m. The initial grade is -3.5% and the final grade is 0.5%. Determine the stationing and elevation of the PVT, PVI and the lowest point on the curve.
Please I need The right answer for this question as soon as possible. A sag vertical...
Please I need The right answer for this question as soon as possible. A sag vertical curve (equal tangent) has PVI at station 212+00 and elevation 540.75 ft. The initial grade is -2.5% and the final grade is +4.5%. The length of the curve is 900 ft. Determine the following, 1. Stationing of the low point, PVC, and PVT. 2. Elevation at station 213+00, PVC, low point, and PVT.
An existing equal-tangent sag vertical curve is designed for 60 mi/h. The initial grade is -3%...
An existing equal-tangent sag vertical curve is designed for 60 mi/h. The initial grade is -3% and the elevation of the PVT is 754 ft. The PVC of the curve is at station 134 + 16 and the PVI is at 137 + 32. An overpass is being constructed directly above the PVI. The highway is for cars only (AASHTO minimum and recommended structure clearances do not apply) and the overpass design assumes the driver's eye height is set conservatively...
An existing equal-tangent sag vertical curve is designed for 60 mi/h. The initial grade is -3%...
An existing equal-tangent sag vertical curve is designed for 60 mi/h. The initial grade is -3% and the elevation of the PVT is 754 ft. The PVC of the curve is at station 134 + 16 and the PVI is at 137 + 32. An overpass is being constructed directly above the PVI. The highway is for cars only (AASHTO minimum and recommended structure clearances do not apply) and the overpass design assumes the driver's eye height is set conservatively...
) An equal-tangent crest vertical curve is designed for 100 km/h. The initial grade is +3.4%...
) An equal-tangent crest vertical curve is designed for 100 km/h. The initial grade is +3.4% and the final grade is negative. Draw the curve. What is the elevation difference between the PVC and the high point of the curve?
An equal-tangent crest vertical curve is being designed for a speed of 55 mph. The curve...
An equal-tangent crest vertical curve is being designed for a speed of 55 mph. The curve connects grades of 2% and -3.5% in the direction of interest. The curve high point is at station 110+00 and has an elevation of 500 ft. What is the station and elevation of the PVC and the PVI?
The PVI of a vertical curve is at station 110 + 00 and elevation 1100.00 ft....
The PVI of a vertical curve is at station 110 + 00 and elevation 1100.00 ft. The vertical curve is equal tangent, 600ft long, and connects an initial grade of +1.30% and a final grade of –1.10%. The vertical curve crosses a 3ft diameter pipe at right angles. The pipe is located at station 112 + 00 and its centerline is at elevation 1093.00 ft. a) Using offsets, determine the depth, below the surface of the curve, to the top...
i would really appreciated if answer this question quickly thank you all ! An equal-tangent crest...
i would really appreciated if answer this question quickly thank you all ! An equal-tangent crest vertical curve is designed for 100 km/h. The initial grade is +3.4% and the final grade is negative. Draw the curve. What is the elevation difference between the PVC and the high point of the curve?
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%;...
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%; VPI sta = 28+50.00 ft.; VPI elev = 609.35 ft., determine the: a. (1 pt.) BVC station b. (1 pt.) EVC station c. (1 pt.) BVC elevation d. (1 pt.) EVC Elevation e. (3 pts.) Elevations on the curve at full stations f. (3 pts.) Elevations on the tangents at full stations g. (2 pts.) Tangent offsets at full stations h. (2 pts.) High/low...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT