Question

Determine the elevations for each standard station between PVC and PVT from a vertical curve connecting a 3% slope to a -5% slope. The PVC and PVT stations are 112 + 22 and 119 + 64, respectively. The elevation of the PVI is 1235 feet.

Answer #1

A 1,800 ft. long sag vertical curve (equal tangent) has PVC at
Station 145+10 and elevation 1,280 ft. The initial grade is -2.5%
and final grade is +4.8%. Determine the elevation and stationing of
PVI and PVT.

A 182.880m equal tangent sag curve has the PVC at station
5+181.600 and elevation 304.800m. The initial grade is -3.5% and
the final grade is 0.5%. Determine the stationing and elevation of
the PVT, PVI and the lowest point on the curve.

A sag vertical curve has the PVC at station 88+00 and PVT at
station 94+25. The back grade is -3.5% and the forward grade is
+2%. The length of the vertical curve is.................ft

Determine the curve length required so that the elevation on the
track at station 126 + 50 is exactly 650 feet. the tangential point
of intersection associated with the curve in question is located at
station 127 + 10 at an elevation of 633 feet. the slopes to PVC and
PVT are -5% and 3% respectively.

Problem #4: Vertical curve
A vertical curve is define by gradient lines. The gradient of
the back tangent is +4.2% and the
gradient of the forward tangent is -3.75%. The BVC station is at
45+00 and has an elevation of
215.00 feet. For a vertical curve with a length of 12 stations,
determine the following:
a. The station and elevation of the PVI.
b. The station and elevation of the EVC.
c. The elevation of the vertical curve at station...

A
vertical curve is joining -4% with -2% gradient, determine the
minimum length of the curve using all applicable criteria. Speed on
the curve will be 60mph. Also, find out elevations of intermediate
stations on the curve for layout. The PVI is at station 31+50 and
elevation 101ft. (using K-values to find the curve length)

Determine the minimum length of a vertical curve necessary for
it to be adequate, under the visibility criteria for braking, for a
design speed of 80 mph. The slopes corresponding to the PVC and PVT
of the curve in question are 4% and -3% respectively. the PVI
station is 120 + 70 and its elevation is 810 meters. The
coefficient of lateral friction is 0.08. All circular curves in the
segment under study have been designed using an 8% superelevation...

An
existing equal-tangent sag vertical curve is designed for 60 mi/h.
The initial grade is -3% and the elevation of the PVT is 754 ft.
The PVC of the curve is at station 134 + 16 and the PVI is at 137 +
32. An overpass is being constructed directly above the PVI. The
highway is for cars only (AASHTO minimum and recommended structure
clearances do not apply) and the overpass design assumes the
driver's eye height is set conservatively...

An existing equal-tangent sag vertical curve is designed for 60
mi/h. The initial grade is -3% and the elevation of the PVT is 754
ft. The PVC of the curve is at station 134 + 16 and the PVI is at
137 + 32. An overpass is being constructed directly above the PVI.
The highway is for cars only (AASHTO minimum and recommended
structure clearances do not apply) and the overpass design assumes
the driver's eye height is set conservatively...

For a vertical curve with the following data: L = 425.00 ft.;
g1= -2.50%; g2= +0.90%; VPI sta = 28+50.00 ft.; VPI elev = 609.35
ft., determine the: a. (1 pt.) BVC station b. (1 pt.) EVC station
c. (1 pt.) BVC elevation d. (1 pt.) EVC Elevation e. (3 pts.)
Elevations on the curve at full stations f. (3 pts.) Elevations on
the tangents at full stations g. (2 pts.) Tangent offsets at full
stations h. (2 pts.) High/low...

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