Question

A −2.50%−2.50% grade meets a +1.75%+1.75% grade at station 44+25 and elevation 3388.76 ftft, 400-ftft curve,...

A −2.50%−2.50% grade meets a +1.75%+1.75% grade at station 44+25 and elevation 3388.76 ftft, 400-ftft curve, stakeout at half stations.

Part A: Determine the elevation at the low point of the curve.

Part B: Determine the station at the low point of the curve

Engineering   Civil-Engineering   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 3.0% grade passing at station 20+00.00 at an elevation of 99.10 m meets a -2.0%...
A 3.0% grade passing at station 20+00.00 at an elevation of 99.10 m meets a -2.0% grade passing at station 20+50.00 at an elevation of 99.60 m. Please note that these two elevations and stations DO NOT correspond to BVC and EVC. a) Determine the station and elevation of the point of intersection of the two grades. b) If the highest point on the curve must lie at station 20+55.00, find the elevation of this point and the length of...
Problem 3.           A +2.35% grade meets a -2.20% grade at station 45+50.00 and elevation 695.00 feet...
Problem 3.           A +2.35% grade meets a -2.20% grade at station 45+50.00 and elevation 695.00 feet (PIVC or VPI). An 800-foot (8 station) vertical curve is planned. Draw a sketch and find the following: a. The station and elevation of the PCVC (BVC) (5 points) b. The station and elevation of the PTVC (EVC) (5 points) c. The elevation (on the curve) of station 44+00.00 (5 points) d. The vertical offset for station 44+00.00 (5 points) e. The station and...
A parabolic curve has a descending grade of -0.8% which meets an ascending grade of 0.6%...
A parabolic curve has a descending grade of -0.8% which meets an ascending grade of 0.6% at station 10+020. The maximum allowable change of grade per 20 m station is 0.20%. Elevation at station 10+020 is 240.60 m. a) Compute the length of the curve; b) Compute the horizontal distance of the lowest point from station 10+020; c) Compute for the vertical distance from PI to the curve; d) Compute the elevation of the lowest point of the curve; e)...
A -6.00% grade and a +2.00% grade intersect at station 20+00. The two grades are to...
A -6.00% grade and a +2.00% grade intersect at station 20+00. The two grades are to be connected by a vertical curve 400 ft long. The elevation of the BVC is 348.52. What is the... a. Elevation on the curve of the low/high point? b. Elevation of the curve at station 19+00 c. Elevation of the tangent at station 21+00 d. Elevation of the curve at station 21+50 e. Elevation of the curve at station 18+50
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%;...
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%; VPI sta = 28+50.00 ft.; VPI elev = 609.35 ft., determine the: a. (1 pt.) BVC station b. (1 pt.) EVC station c. (1 pt.) BVC elevation d. (1 pt.) EVC Elevation e. (3 pts.) Elevations on the curve at full stations f. (3 pts.) Elevations on the tangents at full stations g. (2 pts.) Tangent offsets at full stations h. (2 pts.) High/low...
A +1.75% grade intersects a -2.25% grade at 32+50.00 and elevation 1015.00. An existing overpass is...
A +1.75% grade intersects a -2.25% grade at 32+50.00 and elevation 1015.00. An existing overpass is located at station 31+56.50. Its underside elevation is 1022.50 ft. What is the minimum curve length which will provide 12 ft of clearance under the overpass?
A +9.00% grade intersects a -7.00% at station 50+70.26 and elevation 239.12 ft. A 400.00 ft....
A +9.00% grade intersects a -7.00% at station 50+70.26 and elevation 239.12 ft. A 400.00 ft. curve will be used to connect the two grades. Compute: (1) Station and elevation for the curve's endpoints (2) Elevations and grades at full stations (3) Station and elevation of the curve's highest and/or lowest points First, draw a sketch
A 182.880m equal tangent sag curve has the PVC at station 5+181.600 and elevation 304.800m. The...
A 182.880m equal tangent sag curve has the PVC at station 5+181.600 and elevation 304.800m. The initial grade is -3.5% and the final grade is 0.5%. Determine the stationing and elevation of the PVT, PVI and the lowest point on the curve.
The PVI of a vertical curve is at station 110 + 00 and elevation 1100.00 ft....
The PVI of a vertical curve is at station 110 + 00 and elevation 1100.00 ft. The vertical curve is equal tangent, 600ft long, and connects an initial grade of +1.30% and a final grade of –1.10%. The vertical curve crosses a 3ft diameter pipe at right angles. The pipe is located at station 112 + 00 and its centerline is at elevation 1093.00 ft. a) Using offsets, determine the depth, below the surface of the curve, to the top...
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade...
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade of +1.5%. The PVI of the two grades is at station 33 + 75 and elevation of 540 m above the datum level. The elevation at station 34 + 40 must be 541 m above the datum level in order to Accommodate a street, which crosses the road. Determine; ( According to TRH17) i. The length of the curve. ii. The elevation and station...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT