Question

The PVI of a vertical curve is at station 110 + 00 and elevation 1100.00 ft. The vertical curve is equal tangent, 600ft long, and connects an initial grade of +1.30% and a final grade of –1.10%. The vertical curve crosses a 3ft diameter pipe at right angles. The pipe is located at station 112 + 00 and its centerline is at elevation 1093.00 ft.

a) Using offsets, determine the depth, below the surface of the curve, to the top of the pipe;

b) For a car with low ground clearance, collision with any object higher than 0.5ft may cause damage to the vehicle. For this type of car, what is the safe driving speed on this curve?

Answer #1

A 1,800 ft. long sag vertical curve (equal tangent) has PVC at
Station 145+10 and elevation 1,280 ft. The initial grade is -2.5%
and final grade is +4.8%. Determine the elevation and stationing of
PVI and PVT.

An equal-tangent crest vertical curve is being designed for a
speed of 55 mph. The curve connects grades of 2% and -3.5% in the
direction of interest. The curve high point is at station 110+00
and has an elevation of 500 ft. What is the station and elevation
of the PVC and the PVI?

A
-6.00% grade and a +2.00% grade intersect at station 20+00. The two
grades are to be connected by a vertical curve 400 ft long. The
elevation of the BVC is 348.52.
What is the...
a. Elevation on the curve of the low/high point?
b. Elevation of the curve at station 19+00
c. Elevation of the tangent at station 21+00
d. Elevation of the curve at station 21+50
e. Elevation of the curve at station 18+50

Problem #4: Vertical curve
A vertical curve is define by gradient lines. The gradient of
the back tangent is +4.2% and the
gradient of the forward tangent is -3.75%. The BVC station is at
45+00 and has an elevation of
215.00 feet. For a vertical curve with a length of 12 stations,
determine the following:
a. The station and elevation of the PVI.
b. The station and elevation of the EVC.
c. The elevation of the vertical curve at station...

Please I need The right answer for this question as soon as
possible.
A sag vertical curve (equal tangent) has PVI at station 212+00
and elevation 540.75 ft. The initial grade is -2.5% and the final
grade is +4.5%. The length of the curve is 900 ft. Determine the
following,
1. Stationing of the low point, PVC, and PVT.
2. Elevation at station 213+00, PVC, low point, and PVT.

A sag vertical curve has the PVC at station 88+00 and PVT at
station 94+25. The back grade is -3.5% and the forward grade is
+2%. The length of the vertical curve is.................ft

A horizontal curve on a three-lane highway with 12-ft lanes has
a PC located at station 10+00 and PT at station 13+70. The central
angle is 25 degrees, the superelevation is 4%, and 40 ft of
clearance is available between an obstruction and the centerline.
Determine the maximum safe design speed to the nearest 5 mph.

A 816-ft sag curve (-2% to +4%) has its PVC at station 8+00 and
elevation 125.64’.
a. What is the design speed of this curve?
b. Determine the station and elevation of the point on the curve
where the slope is +1%.

A 182.880m equal tangent sag curve has the PVC at station
5+181.600 and elevation 304.800m. The initial grade is -3.5% and
the final grade is 0.5%. Determine the stationing and elevation of
the PVT, PVI and the lowest point on the curve.

An unequal tangent vertical curve has the following elements:
g1=-3.25%, g2=1.75%, total length = 500.00’, length of curve 1 is
150’, length of curve 2 is 350’, PVI station is 12+00, PVI
elevation is 275.00’
Using the vertical curve, what is the station and elevation of
the high/low point of the curve?

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