Question

A parabolic curve has a descending grade of -0.8% which meets an ascending grade of 0.6% at station 10+020. The maximum allowable change of grade per 20 m station is 0.20%. Elevation at station 10+020 is 240.60 m.

a) Compute the length of the curve;

b) Compute the horizontal distance of the lowest point from station 10+020;

c) Compute for the vertical distance from PI to the curve;

d) Compute the elevation of the lowest point of the curve;

e) Compute the elevation of station 10+000.

Answer #1

A vertical summit parabolic curve has vertical offset of 0.375
m. from the curve to the grade tangent at Station 10 + 050. The
curve has a slope of +4% and -2% grades intersecting at the P.I.
The offset distance of the curve at P.I. is equal to 1.5m. If the
stationing of the P.C. is at 10 + 000.
Compute the
(a) required length of curve (b) horizontal distance of the
vertical curve turning point from the point of...

A vertical parabolic sag curve of Lapulapu underpass has grade
of -4% followed by a grade of +2% intersecting at station 12+150.80
at elevation 124.80 m. above sea level. The change of grade of the
sag curve is restricted to 6%.
Compute the length of curve.
Compute the elevation of the lowest point of the curve.
Compute the elevation at station 12+125.60

the
rate of change of the grade of a parabolic summit curve is 0.5%.
the grade of ascending and descending tangents are 6% and -2.0%
respectively. the elecation of VPT is 200 ft at Sta 15+80.
determine the:
a.) length of curve
b.) elecation of the summit
c.)location of the summit
d.)the vertical distance from VPI to the curve
e.)elevation at Sta 06+80

A vertical parabolic curve is to connect a back tangent of -3%
and a forward tangent of +4%. The change of grade is 0.60% per 20 m
station. The stationing of PC is 17+428 with an elevation of 200 m.
Compute the:
a) length of the parabolic curve;
b) stationing of PT (format: 00+000.00);
c) elevation of PT;
d) elevation of the lowest point of the curve;
e) elevation at Station 17+544.67.

A 3.0% grade passing at station 20+00.00 at an elevation of
99.10 m meets a -2.0% grade passing at station 20+50.00 at an
elevation of 99.60 m. Please note that these two elevations and
stations DO NOT correspond to BVC and EVC.
a) Determine the station and elevation of the point of
intersection of the two grades.
b) If the highest point on the curve must lie at station
20+55.00, find the elevation of this point and the length of...

A vertical curve is needed to connect an entry grade of ‐2.4% to
an exit grade of +1.5%. The PVI of the two grades is at station 33
+ 75 and elevation of 540 m above the datum level. The elevation at
station 34 + 40 must be 541 m above the datum level in order to
Accommodate a street, which crosses the road. Determine; (
According to TRH17)
i. The length of the curve. ii. The elevation and station...

Question Two.
Given the following measurements taken in the field
The initial grade (G1 = + 4%)
Station of BC =1+100.
PI elevation = 181.4 m
Design level at distance L/2 from BC =177.4 m.
Design level at distance L/2+40 =176.75 m.
Determine the following.
1 Length of the vertical curve. (14 M).
2 The station and elevation of the highest point (10 M)
3 The station and elevation of EC (6 M)

A vertical curve has an incoming grade of +4.4% and an exit
grade of -2.2%. The length of the curve is 450.00 ft. The
intersection of the grades is at 10+00 and the elevation at that
point is 440.00.
Compute the elevation of the +00 points on the curve. Then
determine the location and elevation of the highest point on the
curve. If there is an existing bridge at this location over the
proposed road, and the elevation of its...

A crest vertical curve joining a +3 percent and a -4 percent
grade is to be designed with a length of 2184 ft and the Station of
BVC is ( 334 + 68) at an elevation of 217.24 ft. The distance from
BVC at station (339 + :00) is

A vertical summit curve has tangent grades of +2.5% and -1.5%
intersecting at station 12+460.12 at an elevation of 150m above sea
level. If the length of the curve is 182m:
a. Compute the length of the passing sight distance.
b. Compute the stationing of the highest point of the curve.
c. Compute the elevation of the highest point of the curve.

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