Question

Problem 3. A +2.35% grade meets a -2.20% grade at station 45+50.00 and elevation 695.00 feet (PIVC or VPI). An 800-foot (8 station) vertical curve is planned. Draw a sketch and find the following:

a. The station and elevation of the
PCVC (BVC) *(5 points)*

b. The station and elevation of the
PTVC (EVC) *(5 points)*

c. The elevation (on the curve) of
station 44+00.00 *(5 points)*

d. The vertical offset for station
44+00.00 *(5 points)*

e. The station and elevation of the
high point for this curve. *(5 points)*

Answer #1

A 3.0% grade passing at station 20+00.00 at an elevation of
99.10 m meets a -2.0% grade passing at station 20+50.00 at an
elevation of 99.60 m. Please note that these two elevations and
stations DO NOT correspond to BVC and EVC.
a) Determine the station and elevation of the point of
intersection of the two grades.
b) If the highest point on the curve must lie at station
20+55.00, find the elevation of this point and the length of...

Problem #4: Vertical curve
A vertical curve is define by gradient lines. The gradient of
the back tangent is +4.2% and the
gradient of the forward tangent is -3.75%. The BVC station is at
45+00 and has an elevation of
215.00 feet. For a vertical curve with a length of 12 stations,
determine the following:
a. The station and elevation of the PVI.
b. The station and elevation of the EVC.
c. The elevation of the vertical curve at station...

A −2.50%−2.50% grade meets a +1.75%+1.75% grade at station 44+25
and elevation 3388.76 ftft, 400-ftft curve, stakeout at half
stations.
Part A: Determine the elevation at the low
point of the curve.
Part B: Determine the station at the low point
of the curve

.A crest vertical curve joining a +3 percent and a-4 percent
grade is to be designed for 40 Km/h. If the tangents intersect at
station (K20+ 60.00) at an elevation of 200 m, determine the
stations and elevations of the BVC and EVC. Also, calculate the
elevations of intermediate points on the curve at the whole
stations.

A
+9.00% grade intersects a -7.00% at station 50+70.26 and elevation
239.12 ft. A 400.00 ft. curve will be used to connect the two
grades. Compute:
(1) Station and elevation for the curve's endpoints
(2) Elevations and grades at full stations
(3) Station and elevation of the curve's highest and/or lowest
points
First, draw a sketch

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