Question

For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%; VPI sta = 28+50.00 ft.; VPI elev = 609.35 ft., determine the: a. (1 pt.) BVC station b. (1 pt.) EVC station c. (1 pt.) BVC elevation d. (1 pt.) EVC Elevation e. (3 pts.) Elevations on the curve at full stations f. (3 pts.) Elevations on the tangents at full stations g. (2 pts.) Tangent offsets at full stations h. (2 pts.) High/low point station i. (2 pts.) High/low point elevation j. (2 pts.) Elevation on the curve at station 29+70.00 ft. k. (2 pts.) Elevation on the curve at a point 250.00 ft. from the BVC

Answer #1

Given: L=200 ft equal tangent parabolic curve with g1
= -1.25%, g2 = +1.25%, VPI station = 146+00, and VPI
elevation = 1,895.00 ft.
a. Compute stationing of BVC.
b. Compute stationing of EVC.
c. Compute rate of change, r.
d. Compute elevation of BVC.
e. Compute elevation at Station 145+50.

If Sta. VPT= 40+30, L = 400 ft, G1= 3, G2 = -1.8%, and VPC Elev.
= 2563 ft. Calculate the elevations
and stations at a. the low point, b. VPI, and c. VPC?

.A crest vertical curve joining a +3 percent and a-4 percent
grade is to be designed for 40 Km/h. If the tangents intersect at
station (K20+ 60.00) at an elevation of 200 m, determine the
stations and elevations of the BVC and EVC. Also, calculate the
elevations of intermediate points on the curve at the whole
stations.

An unequal tangent vertical curve has the following elements:
g1=-3.25%, g2=1.75%, total length = 500.00’, length of curve 1 is
150’, length of curve 2 is 350’, PVI station is 12+00, PVI
elevation is 275.00’
Using the vertical curve, what is the station and elevation of
the high/low point of the curve?

Use the following data to solve next 3 questions: A vertical
curve with the following parameters: L = 600', g1 = -4%, g2 = -1%,
STA_VPI = 25+00, ELEV_VPI = 672.05' The stations of the BVC and EVC
are:
a. 21+00 and 29+00 b. 19+00 and 31+00 c. 22+00 and 28+00 d.
20+00 and 27+00
The elevation of the BVC of the curve in the previous problem
is:
a.
669.05'
b.
660.05'
c.
684.05'
d.
676.05'
The elevation of the...

Vertical Curve Information :
VPISTA = 15+00
VPIELEV = 320.50 L = 800.00
g1=-4.00% g2=+2.50%
What is the elevation of the low point on the curve?

Problem #4: Vertical curve
A vertical curve is define by gradient lines. The gradient of
the back tangent is +4.2% and the
gradient of the forward tangent is -3.75%. The BVC station is at
45+00 and has an elevation of
215.00 feet. For a vertical curve with a length of 12 stations,
determine the following:
a. The station and elevation of the PVI.
b. The station and elevation of the EVC.
c. The elevation of the vertical curve at station...

PI elev = 85.00 G1=-1%, G2=+2%, low elevation on curve is
103.00. Find L. Show work.
a) 50 stations
b) 55 stations
c) 60 stations
d) 65 stations.

An unequal tangent vertical curve has the following elements:
g1=-3.25%, g2=75%, total length = 500.00’, length of curve 1 is
150’, length of curve 2 is 350’, PVI station is 12+00, PVI
elevation is 275.00’ What is the elevation of the PCC?
276.98’
277.63’
285.63’
265.12’

A
+9.00% grade intersects a -7.00% at station 50+70.26 and elevation
239.12 ft. A 400.00 ft. curve will be used to connect the two
grades. Compute:
(1) Station and elevation for the curve's endpoints
(2) Elevations and grades at full stations
(3) Station and elevation of the curve's highest and/or lowest
points
First, draw a sketch

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