Question

A 3.0% grade passing at station 20+00.00 at an elevation of 99.10 m meets a -2.0%...

A 3.0% grade passing at station 20+00.00 at an elevation of 99.10 m meets a -2.0% grade passing at station 20+50.00 at an elevation of 99.60 m. Please note that these two elevations and stations DO NOT correspond to BVC and EVC.

a) Determine the station and elevation of the point of intersection of the two grades.

b) If the highest point on the curve must lie at station 20+55.00, find the elevation of this point and the length of the curve that meets these conditions.

c) Calculate the station and elevation of the beginning of the vertical curve (BVC), and its end (EVC)

d) Layout this curve at 100 m stations.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Problem 3.           A +2.35% grade meets a -2.20% grade at station 45+50.00 and elevation 695.00 feet...
Problem 3.           A +2.35% grade meets a -2.20% grade at station 45+50.00 and elevation 695.00 feet (PIVC or VPI). An 800-foot (8 station) vertical curve is planned. Draw a sketch and find the following: a. The station and elevation of the PCVC (BVC) (5 points) b. The station and elevation of the PTVC (EVC) (5 points) c. The elevation (on the curve) of station 44+00.00 (5 points) d. The vertical offset for station 44+00.00 (5 points) e. The station and...
.A crest vertical curve joining a +3 percent and a-4 percent grade is to be designed...
.A crest vertical curve joining a +3 percent and a-4 percent grade is to be designed for 40 Km/h. If the tangents intersect at station (K20+ 60.00) at an elevation of 200 m, determine the stations and elevations of the BVC and EVC. Also, calculate the elevations of intermediate points on the curve at the whole stations.
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%;...
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%; VPI sta = 28+50.00 ft.; VPI elev = 609.35 ft., determine the: a. (1 pt.) BVC station b. (1 pt.) EVC station c. (1 pt.) BVC elevation d. (1 pt.) EVC Elevation e. (3 pts.) Elevations on the curve at full stations f. (3 pts.) Elevations on the tangents at full stations g. (2 pts.) Tangent offsets at full stations h. (2 pts.) High/low...
A -6.00% grade and a +2.00% grade intersect at station 20+00. The two grades are to...
A -6.00% grade and a +2.00% grade intersect at station 20+00. The two grades are to be connected by a vertical curve 400 ft long. The elevation of the BVC is 348.52. What is the... a. Elevation on the curve of the low/high point? b. Elevation of the curve at station 19+00 c. Elevation of the tangent at station 21+00 d. Elevation of the curve at station 21+50 e. Elevation of the curve at station 18+50
A +9.00% grade intersects a -7.00% at station 50+70.26 and elevation 239.12 ft. A 400.00 ft....
A +9.00% grade intersects a -7.00% at station 50+70.26 and elevation 239.12 ft. A 400.00 ft. curve will be used to connect the two grades. Compute: (1) Station and elevation for the curve's endpoints (2) Elevations and grades at full stations (3) Station and elevation of the curve's highest and/or lowest points First, draw a sketch
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade...
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade of +1.5%. The PVI of the two grades is at station 33 + 75 and elevation of 540 m above the datum level. The elevation at station 34 + 40 must be 541 m above the datum level in order to Accommodate a street, which crosses the road. Determine; ( According to TRH17) i. The length of the curve. ii. The elevation and station...
A −2.50%−2.50% grade meets a +1.75%+1.75% grade at station 44+25 and elevation 3388.76 ftft, 400-ftft curve,...
A −2.50%−2.50% grade meets a +1.75%+1.75% grade at station 44+25 and elevation 3388.76 ftft, 400-ftft curve, stakeout at half stations. Part A: Determine the elevation at the low point of the curve. Part B: Determine the station at the low point of the curve
A parabolic curve has a descending grade of -0.8% which meets an ascending grade of 0.6%...
A parabolic curve has a descending grade of -0.8% which meets an ascending grade of 0.6% at station 10+020. The maximum allowable change of grade per 20 m station is 0.20%. Elevation at station 10+020 is 240.60 m. a) Compute the length of the curve; b) Compute the horizontal distance of the lowest point from station 10+020; c) Compute for the vertical distance from PI to the curve; d) Compute the elevation of the lowest point of the curve; e)...
A vertical summit parabolic curve has vertical offset of 0.375 m. from the curve to the...
A vertical summit parabolic curve has vertical offset of 0.375 m. from the curve to the grade tangent at Station 10 + 050. The curve has a slope of +4% and -2% grades intersecting at the P.I. The offset distance of the curve at P.I. is equal to 1.5m. If the stationing of the P.C. is at 10 + 000. Compute the (a) required length of curve (b) horizontal distance of the vertical curve turning point from the point of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT