How many grams of ice at 0.0 degress C must be added to 26.2 g of water at 21 deg C to give a final temp in the flask of 0.5 deg C?
+Qice = -Qwater
mst(ice)=-mst(water)
m*2.03*(0-0.5) = -26.2*4.18*(21-0.5)
m =-2245.078/(-1.015)
mass of ice = 2211.89g
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