Question

how many moles of gas would have a pressure of 0.75 atm at 0.0 degress Celsius in a 45 mL flask?

Answer 1

The ideal gas equation is:

P * V = n * R * T

Here, P is the pressure = 0.75 atm

V is the volume of the gas = 45 mL = 0.045 L

T is the temperature in kelvin scale = 0 ⁰C = (0 + 273 ) K = 273 K

R is the universal gas constant = 0.082 lit atm mole^-1 K^-1

n = numbers of moles of the gas = ?

Putting the values in the equation, we get:

0.75 atm * 0.045 Liter = n * 0.082 lit atm mole^-1 K^-1 * 273 K

So, n = (0.75* 0.045)/ (0.082 * 273) mole = 0.0015 mole

Moles of gas = 0.0015 mole