Question

Point charges q1 = -4.32 nC and q2 = +4.32 nC are separated by 3.55 mm, forming an electric dipole. The charges are in a uniform electric field whose direction makes an angle of 36.64° with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 7.63 × 10-9 N.m? (Give your answer in decimal using N/C as unit)

Answer 1

answer) we know the formula

=PEsin............................1)

=7.63*10^-9N.m

P=4.32*10^-9C*3.55*10^-3m=1.5336*10^-11C/m

so now from eqn 1)

E=/Psin=(7.63*10^-9N.m)/1.5336*10^-11C/m*sin(36.64)=8.3367*10²N/C

so the answer is 8.34*10²N/C or 833.7 N/C or 833.67 N/C. or 8.3367*10²N/C