Question

How many hydrogens are in C7HxF2NO?

(which has 1 ring and 3 double bonds)

Answer 1

DOUBLE BOND EQUIVALENT = 1 + 3 = 4 (compound has 1 ring and 3 double bonds)

DOUBLE BOND EQUIVALENT = ( a+1) - (b-c+f)/2

where

a = number of carbon atoms in the compound

b = number of hydrogen atoms in the compound

c = number of nitrogen atoms in the compound

f = number of halogen atoms in the compound

4 = ( 7 + 1) - ( b - 1 + 2 ) /2

   ( b + 1 ) /2 = 4

b + 1 = 8

b = 7

b = number of hydrogen atoms in the compound = 7

hope it helps you , pls thumbs up .