Question

A restaurant opens at 10:00AM and customers come in according to a Poisson process with an...

A restaurant opens at 10:00AM and customers come in according to a Poisson process with an average of 3 customers per hour.

(a) What is the probability the fourth customer will come in before noon?

(b) What is the probability the second customer will come in between 9:00AM and 11:30AM?

Math   Statistics-And-Probability   
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Homework Answers

Answer #1

lemda = average customers coming per hour = 3

average customers coming in every 2 hours = 3* 2 = 6

P(X=x) in poisson distribution = {e^(rate) * rate^(X)} / X!

Note - in second part , customers coming between 9 am to 11:30 am will be same as 10 am and 11:30 am as the store will open at 10 am

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