What is the molecular formula of a hydrocarbon that has 2 triple bond, 1 double bonds, 1 ring, and 34 carbons?
If the hydrocarbon is completely a ring without any double and triple bonds its molecular formula would be of the form CnH2n
Where, n = number of carbons
So, its molecular formula would be C34H68.
but the question says it has two triple bonds ( 2 pi bond in each triple bond) and 1 double bond ( 1 pi bond in each double bond) which means it has total 5 pi bonds. So, we can say five hydrogens are being substituted by five pi bonds.
Therefore molecular formula would be
=C34H(68 - 5)
= C34H63
Again
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