You are given a vial of 4mEq/mL (234 mg/mL) NaCl. You are also given a 50mL bag of NS.
How would you prepare this order? In other words, how many mL of the NaCl would you inject into the NS?
Given 4 mEq/ml of NaCl
We have to prepare 50 ml of normal saline. Normal saline is 0.9% NaCl which is 154 mEq/1000 ml
We have to prepare normal saline in 50 ml
so 154 mEq / 1000 ml = how much milliequivalent of saline to make 50 ml / 50 ml
= 154 / 1000 x 50 = 7.7 mEq of saline are needed to make normal saline of 50 ml.
4 mEq / ml = 7.7 mEq / x ( volume required)
x= 7.7 / 4 = 1.925 ml.
Hence 1.925 ml of 4 mEq/ml NaCl is diluted with 50 ml of sterile water to make 50 ml bag of NS.
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