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Studies of existing cells to determine the minimum number of genes for a living cell have...

Studies of existing cells to determine the minimum number of genes for a living cell have suggested that 206 genes are sufficient. If the ratio of protein-coding genes is the same in this minimal organism as the genes of Escherichia coli (0.980), how many proteins are represented in these 206 genes? Protein-coding genes = -----------

The Escherichia coli genome contains 4377 genes and 5175720 base pairs. How many base pairs would be required to form the genome of this minimal organism if the genes are the same size as Escherichia coli genes? Base pairs =

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Answer #1

Given that the ratio of protein-coding genes is 0.98.

So the number of protein-coding genes out of 206 genes are 201.88 or 202.

From the E.coli genome - the number of bases present in one gene is 5175720/4377 = 1183 bases per gene.

So the number of bases for 206 genes are - 1183 * 206 = 243698 bases pair.

243698 bases pair would be required to form the genome of this minimal organism if the genes are the same size as Escherichia coli genes

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