Question

Solve the IVP y' = 2x(y-1), y(1) = 2

Solve the IVP y' = 2x(y-1), y(1) = 2

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Consider the IVP (x^2 - 2x)dy/dx = (x-2)y + x^2, y(1)=-2. Solve the IVP. Give the...
Consider the IVP (x^2 - 2x)dy/dx = (x-2)y + x^2, y(1)=-2. Solve the IVP. Give the largest interval over which the solution is defined.
Solve the IVP using the Eigenvalue method. x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 Solve...
Solve the IVP using the Eigenvalue method. x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 Solve the IVP using the Eigenvalue method. x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1
Solve the IVP: , y(0)=3. 2) Solve the DE: . y' = xy^2/ (x^2 +1)
Solve the IVP: , y(0)=3. 2) Solve the DE: . y' = xy^2/ (x^2 +1)
Solve the initial value problem (IVP): (y + x 2 y)y' = y^2 + 1, y(0)...
Solve the initial value problem (IVP): (y + x 2 y)y' = y^2 + 1, y(0) = 1
1.) 25pt) Solve the IVP: (initial value problem) y’ = (3x2 + 4x + 2)/(2(y-1)), y(0)...
1.) 25pt) Solve the IVP: (initial value problem) y’ = (3x2 + 4x + 2)/(2(y-1)), y(0) = -1
solve the IVP y'' - 4y' - 5y = 6e-x,  y(0)= 1, y'(0) = -2
solve the IVP y'' - 4y' - 5y = 6e-x,  y(0)= 1, y'(0) = -2
Solve the IVP with Cauchy-Euler ODE: x^2 y''+3xy'+4y=0; y(1)=0, y’(1)=−2
Solve the IVP with Cauchy-Euler ODE: x^2 y''+3xy'+4y=0; y(1)=0, y’(1)=−2
(b) Solve the separable differential equation                   y'= (7e^-3x+2x^2-xcosx)/-6y^3             &nb
(b) Solve the separable differential equation                   y'= (7e^-3x+2x^2-xcosx)/-6y^3                                              (c) Solve the IVP              x(1-siny)dy=(cosx-cosy-y)dx .                              y(π/2)=0
solve ivp: (y+6x^2)dx + (xlnx-2xy)dy = 0, y(1)=2, x>0
solve ivp: (y+6x^2)dx + (xlnx-2xy)dy = 0, y(1)=2, x>0
Solve the IVP with Cauchy-Euler ODE: x^2 y''+ xy'−16y = 0; y(1) = 4, y'(1) =...
Solve the IVP with Cauchy-Euler ODE: x^2 y''+ xy'−16y = 0; y(1) = 4, y'(1) = 0
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT