Question

Solve the initial value problem (IVP): (y + x 2 y)y' = y^2 + 1, y(0)...

Solve the initial value problem (IVP): (y + x 2 y)y' = y^2 + 1, y(0) = 1

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Answer #1

We solve the given differential equation by using seperation of variables method.

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