Question

Solve the IVP: , y(0)=3. 2) Solve the DE: . y' = xy^2/ (x^2 +1)

Solve the IVP: , y(0)=3.

2) Solve the DE: . y' = xy^2/ (x^2 +1)

Math   Advanced-Math   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Using substitution method we solve the given differential equation.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Solve the DE (x^2)y' + xy = (x^3)(y^2) , subject to y(0) = -0.15
Solve the DE (x^2)y' + xy = (x^3)(y^2) , subject to y(0) = -0.15
Solve the IVP with Cauchy-Euler ODE: x^2 y''+ xy'−16y = 0; y(1) = 4, y'(1) =...
Solve the IVP with Cauchy-Euler ODE: x^2 y''+ xy'−16y = 0; y(1) = 4, y'(1) = 0
solve the IVP y'' - 4y' - 5y = 6e-x,  y(0)= 1, y'(0) = -2
solve the IVP y'' - 4y' - 5y = 6e-x,  y(0)= 1, y'(0) = -2
solve the following IVP: x^2y'' - 5xy' + 5y = 0, y(1) = 3, y'(1) =...
solve the following IVP: x^2y'' - 5xy' + 5y = 0, y(1) = 3, y'(1) = -5
Solve the IVP with Cauchy-Euler ODE: x^2 y''+3xy'+4y=0; y(1)=0, y’(1)=−2
Solve the IVP with Cauchy-Euler ODE: x^2 y''+3xy'+4y=0; y(1)=0, y’(1)=−2
solve ivp: (y+6x^2)dx + (xlnx-2xy)dy = 0, y(1)=2, x>0
solve ivp: (y+6x^2)dx + (xlnx-2xy)dy = 0, y(1)=2, x>0
Solve the IVP using the Eigenvalue method. x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 Solve...
Solve the IVP using the Eigenvalue method. x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 Solve the IVP using the Eigenvalue method. x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1
y''+2y(y')^3=0 ; y(0)=1, y'(0)=1 use u=y' to solve IVP
y''+2y(y')^3=0 ; y(0)=1, y'(0)=1 use u=y' to solve IVP
Given the IVP x * sqrt(x+1) * y'''-y'+xy=0 when y(1/2)=y'(1/2)=-1 , and y''(1/2)=1 determine the larest...
Given the IVP x * sqrt(x+1) * y'''-y'+xy=0 when y(1/2)=y'(1/2)=-1 , and y''(1/2)=1 determine the larest interval for which the apporpriate existsence and uniqueness therom gaurentees the exsistence of a unique solution, show all work and fully justify why andhow you got that interval.
Consider the IVP (x^2 - 2x)dy/dx = (x-2)y + x^2, y(1)=-2. Solve the IVP. Give the...
Consider the IVP (x^2 - 2x)dy/dx = (x-2)y + x^2, y(1)=-2. Solve the IVP. Give the largest interval over which the solution is defined.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT