Question

solve the IVP

y'' - 4y' - 5y = 6e^{-x}, y(0)= 1, y'(0) =
-2

Answer #1

Use the definition of the Laplace transform to solve the
IVP:
4y''− 4y' + 5y = δ(t), y(0) = −1, y'(0) = 0.

Solve the IVP with Cauchy-Euler ODE: x^2 y''+3xy'+4y=0; y(1)=0,
y’(1)=−2

solve y''+4y'+4y=0 y(0)=1, y'(0)=4 IVP

solve the following IVP:
x^2y'' - 5xy' + 5y = 0, y(1) = 3, y'(1) = -5

y'' + 4y' + 5y = δ(t − 2π),
y(0) = 0, y'(0) = 0
Solve the given IVP using the Laplace Transform. any help
greatly appreciated :)

(differential equations): solve for x(t) and y(t)
2x' + x - (5y' +4y)=0
3x'-2x-(4y'-y)=0
note: Prime denotes d/dt

Solve the IVP y¨ − 5 y˙ + 4y = e^t , y(0) = 3, y˙(0) = 1/3

solve
y"-4y+5y=20 sehnt, y(0)=0, y'(0)=0

Differential Equations. Solve the following IVP. Y''(Double
Prime) + 6Y'(Prime)+5Y =0, Y'(Prime)(0) =0, Y(0)=1

Use Laplace Transforms to solve the following IVPs .
4y′′+4y′+5y=−t ; y(0)=0 , y′(0)=0

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