Question

solve ivp: (y+6x^2)dx + (xlnx-2xy)dy = 0, y(1)=2, x>0

Answer #1

differential equations solve
(2xy+6x)dx+(x^2+4y^3)dy, y(0)=1

Solve the following differential equations.
a.) dy/dx+2xy=x, y(0)=2
b.) ?^2(dy/dx)−?y=−y^2

Consider the IVP (x^2 - 2x)dy/dx = (x-2)y + x^2, y(1)=-2. Solve
the IVP. Give the largest interval over which the solution is
defined.

(2xy+x^2+3y^2)dy/dx+(y^2+2xy+3x^2)=0

Solve: 1.dy/dx=(e^(y-x)).secy.(1+x^2),y(0)=0.
2.dy/dx=(1-x-y)/(x+y),y(0)=2 .

Solve the following DE:
2xy^2 + 4 = 2(3 - x^2 y)dy/dx ; y(-1) = 8

Solve (2xy/x^2+1-2x)dx-(2-ln(x^2+1))dy=0, y(5)=0. Write the
solution in the explicit form. please explain steps Thanks!

exact differential equation, (2xy+x)dx+(x^2+y)dy=0

solve the differential equation
(2y^2+2y+4x^2)dx+(2xy+x)dy=0

1)Consider the following initial-value problem.
(x + y)2 dx + (2xy + x2 − 2) dy =
0, y(1) = 1. Let af/ax = (x + y)2 =
x2 + 2xy + y2. Integrate each term of this
partial derivative with respect to x, letting
h(y) be an unknown function in y.
f(x, y) = + h(y)
Solve the given initial-value problem.
2) Solve the given initial-value problem.
(6y + 2t − 3)
dt + (8y + 6t
− 1) dy...

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