Private nonprofit four-year colleges charge, on average, $26,516
per year in tuition and fees. The standard deviation is $7,429.
Assume the distribution is normal. Let X be the cost for a randomly
selected college. Round all answers to 4 decimal places where
possible.
a. What is the distribution of X? X ~ N(,)
b. Find the probability that a randomly selected Private nonprofit
four-year college will cost less than 22,272 per year.
c. Find the 62nd percentile for this distribution. $ (Round to the
nearest dollar.)
Solution :
Given that ,
mean = = 26516
standard deviation = = 7429
a)
The distribution of X is,
X ~ N( , )
X ~ N(26516 , 7429)
b)
P(x < 22272) = P((x - ) / < (22272 - 26516) / 7429)
= P(z < -0.57)
= 0.2843 Using standard normal table,
Probability = 0.2843
c)
The z - distribution of the 62% is,
P( Z < z ) = 62 %
P( Z < z ) = 0.62
P( Z < 0.31 ) = 0.62
z = 0.31
Using z - score formula,
X = z * +
= 0.31 * 7429 + 26516
= 28818.99
= $28819
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